X^2-19x-840=0

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Solution for X^2-19x-840=0 equation: 



X^2-19X-840=0

a = 1; b = -19; c = -840;
Δ = b2-4ac
Δ = -192-4·1·(-840)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-61}{2*1}=\frac{-42}{2}
=-21
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+61}{2*1}=\frac{80}{2}
=40
$

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